本帖最后由 zczczcle 于 2016-2-1 12:51 编辑
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2 h3 y! s# P7 n# i b6 }首先,这并不能预测下一个boss具体刷在哪,不过你能通过我的解读知道,boss是怎么个刷法。: G, O, k6 e9 @3 _# q4 c+ U
其次,如果你有挂(付费的每天更新的那种),或者自己会解封包的话,你就能知道附近是否出现小boss了,在附近的话你还能知道他的位置。; g- j) q1 ]: z$ x6 R# Y% s
kuqitt 这位大哥提到打开MonsterList文件第一个数字是0是乱刷,但是后来又不确定很疑惑,原因就在于那个0,1,2,3,4和乱刷与否并无关系,或许是凑巧。
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) M6 k! Z8 f+ i! a N部分选取代码,稍后解读:$ n- w9 x* S$ ~/ k
WORD wNowTeamId = 0;
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+ m, m! y5 c. ~/ Y f _snprintf( szFileName, 256-1, "%s//Monster//MonsterList",g_pBase->GetObjectFilePath() );
# t& Y; O+ N$ u/ o* m: j3 V4 e szFileName[256-1] = '\0';4 h7 ^& J+ C4 s: ]* l% D" s
_snprintf( szMapLog, MAX_MEMO_MSG_LEN-1, "_%d.txt", (int)m_pBase->GetMapId() );
) Z3 O% U, E! ?+ P! O2 H/ J& z szMapLog[MAX_MEMO_MSG_LEN-1] = '\0';3 Y) c" \5 }' D
strcat( szFileName, szMapLog );4 b2 w: s& w+ b5 _$ H" L. y4 w8 o
CInStream MonsterInfo( szFileName ); - v1 f* y3 m& x
if ( MonsterInfo.fail() || MonsterInfo.GetFileSize() == 0 )
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_snprintf( szMapLog, MAX_MEMO_MSG_LEN-1, "***** The Map(%d) Have No Monsters ! *****", GetMapId() );. m* g. `: Y1 c3 x9 d1 k+ F
szMapLog[MAX_MEMO_MSG_LEN-1] = '\0';1 v4 ]2 n H8 R$ L5 j4 x( y: B! d
AddMemoMsg(szMapLog);
) i! h7 J8 q/ w" O return true;
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for( i = 0; i < iColNum; i++ )
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MonsterInfo >> dwTeamId
8 Q0 p) R( Q8 U, c >> dwMonsterId ' F e0 O$ ~2 A; }2 m; [
>> dwX # C2 W/ q, O+ @/ I3 D' @2 |, y
>> dwY
$ F0 `. f2 f1 d7 @, W1 L7 Y+ S0 J >> dwCount;
$ a# X4 H0 N/ A+ |' t; c' n if( wNowTeamId < dwTeamId )
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wNowTeamId = dwTeamId;
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for( j = 0; j < dwCount; j++ )
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6 U8 O. L/ f, m% `0 V! A3 h* \ if( pBaseMonster->GetSpeed() ): }8 w8 `$ g) B, {3 L* d, Z
{
+ n( e8 v { ]3 N; P4 x for( int z = 0; z < 10; z++ )* }$ U: |9 `% C
{
2 J$ J1 }% g% y dwRandX = gf_GetRandom( 14 ) - gf_GetRandom( 14 );
! ~- v: b) z& B dwRandY = gf_GetRandom( 14 ) - gf_GetRandom( 14 );) i( Q& e% h9 D$ h- D7 n
if( !( GetTileFlag( dwX + dwRandX, dwY + dwRandY ) & TILE_ALLOCCULDE ) ) break;5 M" k5 a2 g1 ~2 K- b9 i
else if( z == 9 )
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dwRandX = -1 + gf_GetRandom( 2 ); c* _5 t+ ?4 m5 [( g
dwRandY = -1 + gf_GetRandom( 2 ); n+ P9 |) g9 f) h( `$ Z a
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else) V( R5 N4 |# R
{
4 @' u0 ?% ~0 e4 t/ l) U+ d( C dwRandX = dwRandY = 0;: L/ j3 ^9 @8 ~0 l
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所以我的初步结论是:; M( R- |4 G) a9 s' |
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