本帖最后由 zczczcle 于 2016-2-1 12:51 编辑 6 n, B0 {0 a- d6 K z
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首先,这并不能预测下一个boss具体刷在哪,不过你能通过我的解读知道,boss是怎么个刷法。' w* \7 ^, ]) a! m) Y9 ]
其次,如果你有挂(付费的每天更新的那种),或者自己会解封包的话,你就能知道附近是否出现小boss了,在附近的话你还能知道他的位置。
% h2 Q+ G. w P% xkuqitt 这位大哥提到打开MonsterList文件第一个数字是0是乱刷,但是后来又不确定很疑惑,原因就在于那个0,1,2,3,4和乱刷与否并无关系,或许是凑巧。
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6 v' z! _: B% _/ y1 k( |. q部分选取代码,稍后解读:
" M! G: b* X( k/ O# o1 h X WORD wNowTeamId = 0;
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" ^% h3 H* f+ z* [7 x _snprintf( szFileName, 256-1, "%s//Monster//MonsterList",g_pBase->GetObjectFilePath() );$ M2 A! ~, p9 Q# }
szFileName[256-1] = '\0';: ?$ J& x9 j( E
_snprintf( szMapLog, MAX_MEMO_MSG_LEN-1, "_%d.txt", (int)m_pBase->GetMapId() ); 4 I6 u, f; x+ C7 e3 ~. Y/ m
szMapLog[MAX_MEMO_MSG_LEN-1] = '\0';' {% T1 Z; j" G% D8 z0 g
strcat( szFileName, szMapLog );
8 V" y. s2 V' Y8 t CInStream MonsterInfo( szFileName ); 7 W& Q3 U- K/ ~' q- [/ C& Y
if ( MonsterInfo.fail() || MonsterInfo.GetFileSize() == 0 ) 8 S) n9 h2 p5 E$ v' d! l1 I. K
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_snprintf( szMapLog, MAX_MEMO_MSG_LEN-1, "***** The Map(%d) Have No Monsters ! *****", GetMapId() );( [! t3 I0 r0 p$ a5 ^6 E
szMapLog[MAX_MEMO_MSG_LEN-1] = '\0';
/ ?0 ]: s9 N, ~3 D# z% j AddMemoMsg(szMapLog);
( I6 }* x) @' M8 y* x/ c return true;
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m0 ` J! A( x( d, sfor( i = 0; i < iColNum; i++ )
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MonsterInfo >> dwTeamId - ?! l+ D( w* T6 \, B
>> dwMonsterId
$ U8 R" W+ t5 ^, H9 D >> dwX
/ p/ w& b4 v+ Q B( c# q$ z- i >> dwY
0 u# Z" A X3 L- `" C, F5 N9 W. g >> dwCount; X. r; }- Z- Y7 A. W( b+ `
if( wNowTeamId < dwTeamId )
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wNowTeamId = dwTeamId;# M5 M4 i( \) A3 D
}
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for( j = 0; j < dwCount; j++ )
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if( pBaseMonster->GetSpeed() )
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for( int z = 0; z < 10; z++ )9 N& e8 Q, u9 b) }
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dwRandX = gf_GetRandom( 14 ) - gf_GetRandom( 14 );
5 P4 I7 ?! {. ^! s5 j" Y dwRandY = gf_GetRandom( 14 ) - gf_GetRandom( 14 );6 `1 x( ^) v8 o. a1 F
if( !( GetTileFlag( dwX + dwRandX, dwY + dwRandY ) & TILE_ALLOCCULDE ) ) break;
7 X: Y! l* n _' x. k, s8 G7 T) c else if( z == 9 )
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/ E/ H3 y" |8 `1 K5 b( p dwRandX = -1 + gf_GetRandom( 2 );7 ]4 Y* a5 b7 G! I6 @( ~% y
dwRandY = -1 + gf_GetRandom( 2 );6 c+ @/ [0 R9 E% p) U; E, h1 i% C
}
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}
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{
$ _, T+ x" w& K+ t dwRandX = dwRandY = 0;/ d3 {5 |* ^9 k2 d7 F* ^5 y8 Y
}
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所以我的初步结论是:) N8 {+ q$ x1 D8 @
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