本帖最后由 zczczcle 于 2016-2-1 12:51 编辑 4 Z) c( s2 P( H4 _( i- `
, H( Z* Y0 [. j* o首先,这并不能预测下一个boss具体刷在哪,不过你能通过我的解读知道,boss是怎么个刷法。7 Q2 T1 p9 O. B0 b$ W; L: }
其次,如果你有挂(付费的每天更新的那种),或者自己会解封包的话,你就能知道附近是否出现小boss了,在附近的话你还能知道他的位置。% s# u/ y1 b T& ?
kuqitt 这位大哥提到打开MonsterList文件第一个数字是0是乱刷,但是后来又不确定很疑惑,原因就在于那个0,1,2,3,4和乱刷与否并无关系,或许是凑巧。; g8 f" O) r! K3 I0 e, U4 h& e) \
, X j; ]; K- r% P% w, |部分选取代码,稍后解读:
; d0 k( C8 K; K: t. C" _4 S4 y WORD wNowTeamId = 0; c" R3 Y: o9 _7 I4 ~
) s+ ~8 L% N: y) u7 q _snprintf( szFileName, 256-1, "%s//Monster//MonsterList",g_pBase->GetObjectFilePath() );* V4 ]6 ~& F/ ^+ c' m9 m3 H
szFileName[256-1] = '\0';& r0 x {; u3 }2 f+ k' U0 w
_snprintf( szMapLog, MAX_MEMO_MSG_LEN-1, "_%d.txt", (int)m_pBase->GetMapId() ); & g' ^ F! w% A9 c
szMapLog[MAX_MEMO_MSG_LEN-1] = '\0';$ T" |' ?0 x5 u
strcat( szFileName, szMapLog );: c% c1 L4 `& N
CInStream MonsterInfo( szFileName ); ' g0 L- X* T$ L! i+ P) z
if ( MonsterInfo.fail() || MonsterInfo.GetFileSize() == 0 )
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_snprintf( szMapLog, MAX_MEMO_MSG_LEN-1, "***** The Map(%d) Have No Monsters ! *****", GetMapId() );
6 W, |- V1 H0 W( S6 s szMapLog[MAX_MEMO_MSG_LEN-1] = '\0';
/ |8 e. U9 h) s! b6 i1 d3 c" _) m AddMemoMsg(szMapLog);
! A5 U' F$ v! Q! t4 c return true;) z" p* ?+ w/ k& T) ~& `
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/ [8 \0 \! z1 ?5 T) Efor( i = 0; i < iColNum; i++ ); f6 G+ |! b; Z- d; |: [! I
{
" ~ ]4 g' z6 U MonsterInfo >> dwTeamId
3 Q+ S+ E8 d+ T' }; O >> dwMonsterId
0 M" ^4 t2 k6 s$ K7 w >> dwX
2 L# }2 T3 K7 B. M7 E( T >> dwY 6 Y3 o7 ^5 i6 F7 }* A4 |" S% Y, ~
>> dwCount;
" G# J! c9 h4 O if( wNowTeamId < dwTeamId )
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4 \* j3 Q* X) O/ p2 u6 S wNowTeamId = dwTeamId;% H: @1 m/ {. F2 ~* y
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for( j = 0; j < dwCount; j++ )
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if( pBaseMonster->GetSpeed() )
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for( int z = 0; z < 10; z++ )
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dwRandX = gf_GetRandom( 14 ) - gf_GetRandom( 14 );
7 L) ]/ F: t- N) N dwRandY = gf_GetRandom( 14 ) - gf_GetRandom( 14 );6 O" G9 J7 R( `* ~/ U# s
if( !( GetTileFlag( dwX + dwRandX, dwY + dwRandY ) & TILE_ALLOCCULDE ) ) break;
, s g* j, B8 x else if( z == 9 )
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dwRandX = -1 + gf_GetRandom( 2 );( o- Q; z7 s. H6 @/ |
dwRandY = -1 + gf_GetRandom( 2 ); e- Q3 Y' G# l5 V6 r8 O8 b! Q" R
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}
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dwRandX = dwRandY = 0;; H' Q. Q! b% ^- q$ Q$ v# p
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所以我的初步结论是:2 L0 j3 E$ [/ Y2 T) F1 _& X
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