本帖最后由 zczczcle 于 2016-2-1 12:51 编辑
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4 O6 w: g8 s, ]7 d$ Y* ]首先,这并不能预测下一个boss具体刷在哪,不过你能通过我的解读知道,boss是怎么个刷法。5 j k7 H$ V/ i. Z. ]/ p" E6 F5 A
其次,如果你有挂(付费的每天更新的那种),或者自己会解封包的话,你就能知道附近是否出现小boss了,在附近的话你还能知道他的位置。: c2 \) j0 w0 M! e' U$ Z6 C- I
kuqitt 这位大哥提到打开MonsterList文件第一个数字是0是乱刷,但是后来又不确定很疑惑,原因就在于那个0,1,2,3,4和乱刷与否并无关系,或许是凑巧。
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* c+ g& w. j- V/ H* R- {部分选取代码,稍后解读:& c" G5 [0 {1 z( A: c! \# A7 `
WORD wNowTeamId = 0;
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_snprintf( szFileName, 256-1, "%s//Monster//MonsterList",g_pBase->GetObjectFilePath() );
" }! m' Q" w4 A9 l3 k szFileName[256-1] = '\0';/ M! l% U x f$ g% ?+ M
_snprintf( szMapLog, MAX_MEMO_MSG_LEN-1, "_%d.txt", (int)m_pBase->GetMapId() ); 6 S' M+ l) z4 Y5 v. H4 \( [
szMapLog[MAX_MEMO_MSG_LEN-1] = '\0';
+ `% D$ s* {3 X3 O5 G+ U( Q strcat( szFileName, szMapLog );: r* G5 m) S4 r# |2 b. m- ?# ]
CInStream MonsterInfo( szFileName ); 8 f, t& v) d M! H* Q/ m6 K( b
if ( MonsterInfo.fail() || MonsterInfo.GetFileSize() == 0 )
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_snprintf( szMapLog, MAX_MEMO_MSG_LEN-1, "***** The Map(%d) Have No Monsters ! *****", GetMapId() );$ Q. {! M! ]! n; i5 `0 S2 Z
szMapLog[MAX_MEMO_MSG_LEN-1] = '\0';
5 }' E' N, [. Q6 ~$ E" G AddMemoMsg(szMapLog);! i5 x* Z1 ^$ ?) H* G! K
return true;5 z u+ q a* }5 O' `0 b
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for( i = 0; i < iColNum; i++ )
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MonsterInfo >> dwTeamId $ Q; N7 w6 u$ j4 T7 x
>> dwMonsterId
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0 {1 f3 d; u+ j. y9 M. o >> dwY % ?7 S: J3 x: ^" ^. v' J8 n9 u
>> dwCount;
5 R( w: f' Q. M) v+ K if( wNowTeamId < dwTeamId )% h2 F6 H3 k6 S. U9 V
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wNowTeamId = dwTeamId;6 L! V! F. s. S
}
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for( j = 0; j < dwCount; j++ )
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) A/ M; a$ A6 a' R! ?7 m" s4 Q if( pBaseMonster->GetSpeed() )
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for( int z = 0; z < 10; z++ )
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, {- N* H0 n7 t; {9 P) E& Q* \ dwRandX = gf_GetRandom( 14 ) - gf_GetRandom( 14 );" A5 B2 Y" o0 n8 F% n4 E
dwRandY = gf_GetRandom( 14 ) - gf_GetRandom( 14 );
! b" j+ Z; E( g4 z3 e: g* G4 i if( !( GetTileFlag( dwX + dwRandX, dwY + dwRandY ) & TILE_ALLOCCULDE ) ) break;5 G/ m* q2 K/ f: |2 p; Q- O
else if( z == 9 )/ Z, R1 i, v! ]+ h" L
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dwRandX = -1 + gf_GetRandom( 2 );
% j% O8 R3 z5 Z; p& C ? dwRandY = -1 + gf_GetRandom( 2 );/ a# s4 l; [, F3 ~4 f5 L/ Q
}
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$ J6 L3 Q6 [: X& w0 w, J+ I dwRandX = dwRandY = 0;- \2 n: a6 x: `8 I/ N. D, O
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% c: m: j2 J) r5 |' Z( j$ a所以我的初步结论是:1 C2 T" ?5 Q7 R- ]4 M
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