本帖最后由 zczczcle 于 2016-2-1 12:51 编辑 b* h B! P" k7 {, g2 y/ { v
9 F% b; Z, e G( G% P( \
首先,这并不能预测下一个boss具体刷在哪,不过你能通过我的解读知道,boss是怎么个刷法。
0 c+ V% z5 f- s% e: G+ G1 d其次,如果你有挂(付费的每天更新的那种),或者自己会解封包的话,你就能知道附近是否出现小boss了,在附近的话你还能知道他的位置。1 m( J; v, w2 w+ M1 Q7 S/ @
kuqitt 这位大哥提到打开MonsterList文件第一个数字是0是乱刷,但是后来又不确定很疑惑,原因就在于那个0,1,2,3,4和乱刷与否并无关系,或许是凑巧。
" W9 E* o- ]% C+ y8 v
2 N [& T( m B) a6 Y" L部分选取代码,稍后解读:1 V+ B- O; P5 ]( c: N. a9 ~; M
WORD wNowTeamId = 0;; W. d" x% p( Z! k' l' _, ^
# m J: T( D9 F7 B8 V _snprintf( szFileName, 256-1, "%s//Monster//MonsterList",g_pBase->GetObjectFilePath() );! z7 j* s4 {$ @' X6 {
szFileName[256-1] = '\0';
: T2 m3 r0 A8 w3 E5 R! F; t _snprintf( szMapLog, MAX_MEMO_MSG_LEN-1, "_%d.txt", (int)m_pBase->GetMapId() );
3 I; j: s9 {4 T7 |% W1 F3 O( r szMapLog[MAX_MEMO_MSG_LEN-1] = '\0';
/ Z. N: ?( U& p# q( E7 i2 H" Z7 z b strcat( szFileName, szMapLog );
y5 A; G7 s0 l& @& r P CInStream MonsterInfo( szFileName );
8 f0 A y0 t" L+ i( S( v7 `% U if ( MonsterInfo.fail() || MonsterInfo.GetFileSize() == 0 ) ( N' {) H' I; W( F$ k/ L
{6 u" X% @, [3 `+ H2 `" k
_snprintf( szMapLog, MAX_MEMO_MSG_LEN-1, "***** The Map(%d) Have No Monsters ! *****", GetMapId() );5 S/ j& o3 @+ D$ t, |% N
szMapLog[MAX_MEMO_MSG_LEN-1] = '\0';
3 u* |" \. K0 f t, Q AddMemoMsg(szMapLog);
6 l, g; d- G+ [# l) P return true;+ p. `& s) h8 r$ P9 t F" n
6 T- E* w& `, j+ l- ~: m( ?: H6 m8 P l% z4 @/ e" X( B: I* y
! k& k* x, [! |) Q' N* M
for( i = 0; i < iColNum; i++ )% O7 v4 o. w, i* l" I) J8 h& O
{
3 s: ^7 p" X/ d MonsterInfo >> dwTeamId
4 u R. a6 v( I/ s- Z! ^! p >> dwMonsterId
- U) H& [# ` U( d& W& e b. G >> dwX
A! n) ^; r% _' X' n2 `1 q+ p. K3 V >> dwY
5 h% |# b0 \" S6 ]; h# @ >> dwCount;6 B; E8 p8 J; |* t# Q
if( wNowTeamId < dwTeamId )1 }5 C1 |3 w- p- I
{
2 x5 f* ]. E- o% o3 k5 r+ v5 V3 Y wNowTeamId = dwTeamId;
9 @, }' }1 `" @5 d( O/ t2 o1 R }
: ^1 |3 a, @- g z. S
/ ]# X' F: t# B( V5 u3 @# P; f" C. S: \7 u9 b7 M; h; a' M% I9 q4 I
! m; e4 _4 {- ~6 v
for( j = 0; j < dwCount; j++ )% j9 n6 X! m# B2 p
{
3 `/ @3 O4 E- k d+ i if( pBaseMonster->GetSpeed() )
9 q! l' Z& r/ j+ U( X {+ y5 w- N! V. a5 F; i4 ^; A4 E; T
for( int z = 0; z < 10; z++ )
9 e- a0 L! | i: k7 i6 J4 _- h: Z$ j {2 W7 w) b) \( }$ C" i$ S- S
dwRandX = gf_GetRandom( 14 ) - gf_GetRandom( 14 );( _: [; D0 y( I+ w. L9 `% Y! y, E
dwRandY = gf_GetRandom( 14 ) - gf_GetRandom( 14 );4 r1 z% q5 A# n0 a! \3 d% Q
if( !( GetTileFlag( dwX + dwRandX, dwY + dwRandY ) & TILE_ALLOCCULDE ) ) break;
. A H- h2 ^2 S0 \- B else if( z == 9 )
- q/ ?* ]( P+ e# B& t$ Z% _ {
8 I. N0 o! n) y dwRandX = -1 + gf_GetRandom( 2 );
! P" F! `% C, R- `( j1 a8 x dwRandY = -1 + gf_GetRandom( 2 );' @7 L9 I' X7 {
}
$ c- B0 M+ \" q) E/ ], b }
) e' @ P2 L+ u h7 T }8 E) t) {0 c z8 I7 X1 t9 J( v
else8 w: g0 B- a# o% a, Y- P5 i
{9 V! Q5 [# Q8 B$ e5 I
dwRandX = dwRandY = 0;) k4 f1 a! w4 r1 H+ t j6 e
}
$ p- K& M6 w( x4 b/ C1 \" L+ X8 A2 c1 R9 k: ]8 ]
) j G2 y) K' u" ]. i6 a* Z
3 x# Q( A& h4 P3 O; L
所以我的初步结论是:
& |9 a: I( R3 }2 z i7 x. l- F; g3 L3 P4 G N- r
|