本帖最后由 zczczcle 于 2016-2-1 12:51 编辑 0 I; Q6 n i9 }! S, q
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首先,这并不能预测下一个boss具体刷在哪,不过你能通过我的解读知道,boss是怎么个刷法。
) s: l) o- a! P其次,如果你有挂(付费的每天更新的那种),或者自己会解封包的话,你就能知道附近是否出现小boss了,在附近的话你还能知道他的位置。8 t% L$ u5 ?/ |! H0 X0 X x
kuqitt 这位大哥提到打开MonsterList文件第一个数字是0是乱刷,但是后来又不确定很疑惑,原因就在于那个0,1,2,3,4和乱刷与否并无关系,或许是凑巧。
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部分选取代码,稍后解读:& k, S5 ?0 |$ b7 I. L5 L
WORD wNowTeamId = 0;
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0 H) f2 [; x8 a8 J _snprintf( szFileName, 256-1, "%s//Monster//MonsterList",g_pBase->GetObjectFilePath() );- P. N! f2 f8 @1 e1 V+ f4 E
szFileName[256-1] = '\0';
! Q: h, }( `( I1 W5 x- `/ z% G1 c! ~ _snprintf( szMapLog, MAX_MEMO_MSG_LEN-1, "_%d.txt", (int)m_pBase->GetMapId() ); " `% g! [4 p$ p3 i( Y. V
szMapLog[MAX_MEMO_MSG_LEN-1] = '\0';
% K5 c2 k' m6 ~, q: P strcat( szFileName, szMapLog );
* _( P- q9 S7 A0 y CInStream MonsterInfo( szFileName ); - l8 P2 A5 @& A& w
if ( MonsterInfo.fail() || MonsterInfo.GetFileSize() == 0 ) 5 T) f; A1 R3 i `* I* C, R
{
6 g; p' J% f) P! e2 }9 w _snprintf( szMapLog, MAX_MEMO_MSG_LEN-1, "***** The Map(%d) Have No Monsters ! *****", GetMapId() );
- k* b: H) X; u8 p' A/ d szMapLog[MAX_MEMO_MSG_LEN-1] = '\0';
! E! G5 L+ x N9 b AddMemoMsg(szMapLog);
9 P# ?2 Y6 g0 v1 k% ? return true;6 f9 z7 C4 I" s) l9 c) {
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for( i = 0; i < iColNum; i++ )- p; B6 z$ ^+ T6 D* C1 k' e
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MonsterInfo >> dwTeamId
( g" W" o- X0 t: r >> dwMonsterId 7 G2 Z+ W; w9 L% `
>> dwX
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>> dwCount;9 e1 ?8 d+ ?6 y7 d7 X
if( wNowTeamId < dwTeamId )
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wNowTeamId = dwTeamId;
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for( j = 0; j < dwCount; j++ )
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+ w0 ?6 \' N, A5 R: i" q- _ if( pBaseMonster->GetSpeed() )# t* Q) J7 f1 V" S+ D Y4 `
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for( int z = 0; z < 10; z++ )
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7 m+ i+ m9 D+ b/ N* U dwRandX = gf_GetRandom( 14 ) - gf_GetRandom( 14 );
5 [' m" Z3 d: @) O. y b dwRandY = gf_GetRandom( 14 ) - gf_GetRandom( 14 );& Q" I! K- T- s' j& |5 ~1 P% [" w
if( !( GetTileFlag( dwX + dwRandX, dwY + dwRandY ) & TILE_ALLOCCULDE ) ) break;1 E0 j! C0 T- ~
else if( z == 9 )& u$ M* r4 h% ]5 }2 {
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dwRandX = -1 + gf_GetRandom( 2 );: Z! f; k) m0 L7 U% i( @: k
dwRandY = -1 + gf_GetRandom( 2 );9 i" P# ^3 o# D2 b9 y. I. m$ k8 `: _
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}
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else
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6 x4 m6 p8 p, j4 u, [ dwRandX = dwRandY = 0;
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所以我的初步结论是:
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